# zad 1 # a) (2 * 3^3)/(sin(pi/6)) + log(2401,7) # 112 # b) abs(-9 + 5^-3) + (2^(1/3))^(1/5) # 10.03929 # c) 2^(1/3) * log((3^5 + 5^2 - 12),2) + (3 + (7^(4/3)))^(1/5) # 10.03929 # zad 2 a = c(1,-10,12,3,2,1,-8,4,5) A = matrix(a, 3, 3) b = c(1,3,-1,2,1,5) B = matrix(b,3, 2) # a) det(A) # 572 # b) solve(A) #[,1] [,2] [,3] #[1,] 0.01048951 -0.04020979 0.04895105 #[2,] 0.17132867 0.17657343 0.13286713 #[3,] -0.05944056 0.06118881 0.05594406 # c) t(A) #[,1] [,2] [,3] #[1,] 1 -10 12 #[2,] 3 2 1 #[3,] -8 4 5 # d) A%*%B # [,1] [,2] [,3] #[1,] 1 -10 12 #[2,] 3 2 1 #[3,] -8 4 5 A%*%t(A) #[,1] [,2] [,3] #[1,] 74 -36 -25 #[2,] -36 120 -98 #[3,] -25 -98 170 A%*%A #[,1] [,2] [,3] #[1,] -125 1 -36 #[2,] 18 -22 108 #[3,] 62 43 -67 # e) A[1,] * B[,2] # [1] 2 3 -40 # zad 3 na kolokwium c = c(1,2,5,-2,1,2,5,-3,-1,0,2,1,-2,3,5,2) C = matrix(c, 4, 4) D = c(-7,21,40,2) solve(C,D) # [1] 1 2 0 5 solve(C)[2,3] # [1] -0.1578947 # zad 4 na kolokwium w = (1:100)^2 summary.factor(w%%10) # 0 1 4 5 6 9 # 10 20 20 10 20 20 summary.factor(w%%2 == 0) # FALSE TRUE # 50 50 summary.factor(w%%3 == 0) # FALSE TRUE # 67 33 summary.factor(w%%3 == 0 & w%%2 == 0) # FALSE TRUE # 84 16 # zad 5 na kolokwium w = seq(21,29903, by=7)^3 summary.factor(w %% 100 == 23) #FALSE TRUE # 4226 43 # zad 6